Matematika Sekolah Menengah Pertama Quiz 482/500

10² + 20² =

p¹²³ ÷ p¹¹³ =

2³³ × 2⁵⁰ =

yg terakhir y karena ak mau main ml._. ​

Quiz 482/500

10² + 20² =

p¹²³ ÷ p¹¹³ =

2³³ × 2⁵⁰ =

yg terakhir y karena ak mau main ml._. ​

Jawaban:

1. 500

2. p^10

3. 2^83

Penjelasan dengan langkah-langkah:

1. 10² + 20²

= (10 × 10) + (20 × 20)

= 100 + 400

= 500

2. p^123 ÷ p^113

= p^123-113

= p^10

3. 2^33 × 2^50

= 2^33+50

=2^83

::Jᴀᴡᴀʙᴀɴ::

[tex]1. \: \: \sf10² + 20²[/tex]

[tex] \sf = (10 \times 10) + (20 \times 20)[/tex]

[tex] \sf = 100 + 400[/tex]

[tex] \tt = 500[/tex]

[tex] \\ [/tex]

[tex]2. \: \: \sf \: p¹²³ ÷ p¹¹³ [/tex]

[tex] \sf = p {}^{(123 -113) } [/tex]

[tex] \sf = p {}^{10} [/tex]

[tex] \\ [/tex]

[tex]3. \: \: \sf2³³ × 2⁵⁰ [/tex]

[tex] = \sf2 {}^{(33 + 50)} [/tex]

[tex] \sf = {2}^{83}[/tex]

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